How is 2460edo *actually* notated?
How is 2460edo *actually* notated?
Is there actual material showing it, such as what basic symbols are used and how the diacritics are applied.
- cmloegcmluin
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Re: How is 2460edo *actually* notated?
@FloraC The Extreme precision level of Sagittal's standard JI notation is modeled after 2460-EDO, which uses the full Olympian symbol set, so the notation for 2460-EDO is just every Olympian symbol in order.
Dave has corrected the above crossed-out statements in the next post. Sorry for any confusion.
Normally you could find that in the data tabs of the standard JI notation calculator spreadsheet, but the one that's linked on the site presently is out-of-date (specifically I noticed it's missing the very last step here, the
). I suspect it got reset to an older backup version of itself or something when we did a server upgrade last month. Perhaps you knew this already and checked there but were confused by what you found — if so, very sorry about that! Thanks for alerting us to the problem and I'll update it ASAP. Unfortunately this caused me to realize I've lost access to updating it, too, but that's another issue
Anyway, I still have all the source information in my repo...
The above crossed-out stuff has also been dealt with. Never mind.
....so here you go.
I first used Dave's Athenian-preference to choose between the two options. That worked in 5 out of 6 cases (the 2 other cases of the 8 split minas — the ones above the half-apotome mirror — are not separate cases because for those we just choose the apotome complement of the one we choose below the mirror).
The only tough case was between

and 
. I next checked if their primary commas were consistently mapped in 2460. They were; both the 625M and 11/5M map to 105\2046 as they should. So that didn't break the tie.
Next I checked their complexity using our favorited metric, N2D3P9:
https://en.xen.wiki/w/N2D3P9#Table_of_T ... _by_N2D3P9
Which places the 5/11M above the 625M. So that makes
win.
Which is just as well because the

requires not just one, but two accents.
By the way:
1439 steps in a CG (fifth)
418 steps in a CD (whole tone)
233 steps in a # (chromatic semitone)
185 steps in a BC (diatonic semitone)
0 (
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keep

strike
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strike
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keep
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keep

strike
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keep
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strike
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keep
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strike
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keep
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keep

strike
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keep


strike
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I believe you can take it from there but if you have any other questions let me know.
Dave has corrected the above crossed-out statements in the next post. Sorry for any confusion.
Normally you could find that in the data tabs of the standard JI notation calculator spreadsheet, but the one that's linked on the site presently is out-of-date (specifically I noticed it's missing the very last step here, the



The above crossed-out stuff has also been dealt with. Never mind.
....so here you go.
I first used Dave's Athenian-preference to choose between the two options. That worked in 5 out of 6 cases (the 2 other cases of the 8 split minas — the ones above the half-apotome mirror — are not separate cases because for those we just choose the apotome complement of the one we choose below the mirror).
The only tough case was between





Next I checked their complexity using our favorited metric, N2D3P9:
https://en.xen.wiki/w/N2D3P9#Table_of_T ... _by_N2D3P9
Which places the 5/11M above the 625M. So that makes


Which is just as well because the



By the way:
1439 steps in a CG (fifth)
418 steps in a CD (whole tone)
233 steps in a # (chromatic semitone)
185 steps in a BC (diatonic semitone)
0 (

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I believe you can take it from there but if you have any other questions let me know.
- Dave Keenan
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Re: How is 2460edo *actually* notated?
Hi FloraC. I'm afraid Douglas is mistaken. The Olympian (Extreme precision) symbol set contains 8 more symbols than are needed for 2460edo, and a decision has not previously been made as to which symbol should be used in those cases where there is a choice of two symbols. If you look at the "Boundaries" tab in the JI Notation spreadsheet, you will see these pairs hilited.
In the "Commas" tab of that spreadsheet you will see the primary comma (37-limit) for each symbol. You could convert these to prime-count vectors and then apply the simple map for 2460edo to them, to check that they map to the expected degree of 2460edo, since, strictly speaking, Olympian is based on 233-EDA (apotome), not 2460-EDO.
In choosing which of two valid Olympian symbols to use for a degree of 2460edo, I would favour those whose core symbol is Athenian.
No, there is no such material. But we could decide it here and now.
In the "Commas" tab of that spreadsheet you will see the primary comma (37-limit) for each symbol. You could convert these to prime-count vectors and then apply the simple map for 2460edo to them, to check that they map to the expected degree of 2460edo, since, strictly speaking, Olympian is based on 233-EDA (apotome), not 2460-EDO.
In choosing which of two valid Olympian symbols to use for a degree of 2460edo, I would favour those whose core symbol is Athenian.
- cmloegcmluin
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Re: How is 2460edo *actually* notated?
@Dave Keenan and @FloraC I have corrected my previous post. Hope I've got it in decent order now. Sorry for goofing up in the first place.
- Dave Keenan
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Re: How is 2460edo *actually* notated?
Thanks Douglas. That looks good.
It would also be interesting (some time) to see if it is possible to make a notation for 2460edo using the new Stoic symbols plus the Herculean and Olympian accents. That would be equivalent to dropping all symbols with non-Athenian (Promethean-extension) cores and filling in the gaps by adding more accents to the Athenian cores, then replacing the Athenians with Stoics.
It would also be interesting (some time) to see if it is possible to make a notation for 2460edo using the new Stoic symbols plus the Herculean and Olympian accents. That would be equivalent to dropping all symbols with non-Athenian (Promethean-extension) cores and filling in the gaps by adding more accents to the Athenian cores, then replacing the Athenians with Stoics.
Re: How is 2460edo *actually* notated?
Uh, first, there's no left diacritics vs right diacritics? Then https://sagittal.org/SagittalJI.gif is seriously out of date.
Second, why is promethean involved at all? I figured it's possible to do this
1\
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9\

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And so on.
Second, why is promethean involved at all? I figured it's possible to do this
1\


2\


3\



4\


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7\



8\


9\



10\


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12\

And so on.
- Dave Keenan
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Re: How is 2460edo *actually* notated?
That's correct. There is no longer any need to use right diacritics/accents, particularly now that the Olympian accents are in SMuFL and Bravura. See viewtopic.php?f=10&t=254 and see the last paragraph on page 24 of https://sagittal.org/sagittal.pdf
Yes! Douglas has had a partly-completed updated version of that chart in the works for many months now, but has been distracted by our Regular Temperament Theory simplification/pedagogy project.Then https://sagittal.org/SagittalJI.gif is seriously out of date.
Yes. That's the kind of thing I was suggesting above, as a stepping stone to a possible accented-Stoic notation. But I agree that such an accented-Athenian notation could be used in it's own right, if it could be made to work. However there is a problem where there are more than 13 steps of 2460edo between some pairs of consecutive (unaccented) Athenians. This occurs as follows:Second, why is promethean involved at all? I figured it's possible to do this
1\![]()
2\![]()
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9\![]()
10\![]()
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And so on.





and worst of all


Using symbols from the Promethean extension, such as








Re: How is 2460edo *actually* notated?
14 steps
14 steps
14 steps
and worst of all
17 steps
![]()










For any 14- or 15-step gap I might go for





- Dave Keenan
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Re: How is 2460edo *actually* notated?
You are so right. I went and made the same mistake Douglas did initially. Thanks FloraC.
Yes, you could use the 9-tina accent as a 3-mina accent.